#### 57.6**Question:** Compute \(\cos 45^\circ + \cos 225^\circ\). - United Radiology

February 23, 2026 · United Radiology

["Compute (\cos 45^\circ + \cos 225^\circ): A Step-by-Step Solution for Accurate Results", "Understanding trigonometric identities is essential for solving complex angle problems efficiently. One common challenge is computing expressions involving cosine values of specific angles, such as (\cos 45^\circ + \cos 225^\circ). This article provides a clear and precise breakdown of how to calculate this expression step by step.", "### Step 1: Recall Cosine Values of Key Angles
\nWe begin by identifying the exact values of the cosine functions at the given angles:", "- (\cos 45^\circ = \frac{\sqrt{2}}{2})
\n- (\cos 225^\circ = \cos (180^\circ + 45^\circ) = -\cos 45^\circ = -\frac{\sqrt{2}}{2})
\n(Using the identity (\cos(180^\circ + \ heta) = -\cos \ heta))", "### Step 2: Substitute Known Values
\nNow substitute these values into the original expression:", "[
\n\cos 45^\circ + \cos 225^\circ = \frac{\sqrt{2}}{2} + \left(-\frac{\sqrt{2}}{2}\right)
\n]", "### Step 3: Perform the Addition
\nCombine the terms:", "[
\n\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2} = 0
\n]", "### Final Answer
\n[
\n\boxed{0}
\n]", "## Why This Matters: The Power of Cosine Identities in Trigonometry", "The identity (\cos(180^\circ + \ heta) = -\cos \ heta) is crucial for simplifying expressions involving angles outside the first rotation. Recognizing periodicity and sign changes in trigonometric functions enables faster and more accurate calculations without relying on calculators. Whether studying for exams or solving real-world problems in physics and engineering, mastering these foundational identities is indispensable.", "---", "Key SEO Keywords:
\n(\cos 45^\circ), (\cos 225^\circ), trigonometric identities, cosine addition, exact values, step-by-step math, angle computation, trigonometry basics", "Meta Description:
\nLearn how to compute (\cos 45^\circ + \cos 225^\circ) using exact values and key trigonometric identities. Step-by-step explanation for students and math enthusiasts."]

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