#### 200

February 22, 2026

#### 200

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D(10) = 50, D(20) = 800.
800 = 50 × e^(10k) → e^(10k) = 16 → 10k = ln(16) = 2.7726 → k ≈ 0.27726.
At r = 15: D(15) = 50 × e^(0.27726×5) = 50 × e^(1.3863) ≈ 50 × 4 = <<50*4=200>>200 people/km².
A bioinformatician applies a machine learning model that correctly identifies gene functions with 92% accuracy. If the model analyzes 2,500 genes, and 1,800 are truly annotated, how many non-annotated genes are incorrectly labeled if total errors are distributed uniformly across false positives and false negatives?
Total correct = 92% of 2,500 = 0.92 × 2,500 = <<0.92*2500=2300>>2,300.
Total errors = 2,500 - 2,300 = <<2500-2300=200>>200.

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