\boxed{31.5\sqrt{3} \text{ cm}^2}
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- A_2 = \frac{3\sqrt{3}}{2} \times 11^2 = \frac{3\sqrt{3}}{2} \times 121 = 181.5\sqrt{3} \text{ cm}^2
- \Delta A = A_2 - A_1 = 181.5\sqrt{3} - 150\sqrt{3} = 31.5\sqrt{3} \text{ cm}^2
- Thus, the area of the hexagon increases by:
- Question:** A right circular cone has a height of 12 cm and a base radius of 5 cm. If the radius is doubled while the height remains the same, by what factor does the volume increase?
- The volume \( V \) of a cone is given by:
- V = \frac{1}{3} \pi r^2 h
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