\[ rac{n}{2}(6 + 2n - 2) = 210 \] - United Radiology

["Solving the Equation: ( \frac{n}{2}(6 + 2n - 2) = 210 )", "Understanding and solving equations is a fundamental skill in algebra, especially when dealing with quadratic forms. One interesting equation gaining attention in problem-solving circles is:", "[
\n\dfrac{n}{2}(6 + 2n - 2) = 210
\n]", "This equation involves a linear expression inside a parentheses multiplied by ( \frac{n}{2} ), forming a quadratic expression. Solving it not only helps verify algebraic techniques but also strengthens problem-solving abilities applicable in various STEM fields.", "---", "### Simplifying the Equation", "Start by simplifying the expression inside the parentheses:", "[
\n6 + 2n - 2 = 2n + 4
\n]", "Now, substitute back:", "[
\n\dfrac{n}{2}(2n + 4) = 210
\n]", "Multiply ( \dfrac{n}{2} ) across the terms:", "[
\n\dfrac{n}{2} \cdot 2n + \dfrac{n}{2} \cdot 4 = n^2 + 2n
\n]", "So the equation becomes:", "[
\nn^2 + 2n = 210
\n]", "---", "### Forming a Standard Quadratic Equation", "Bring all terms to one side to form a standard quadratic equation:", "[
\nn^2 + 2n - 210 = 0
\n]", "This is a quadratic equation of the form ( an^2 + bn + c = 0 ), with ( a = 1 ), ( b = 2 ), ( c = -210 ).", "---", "### Solving the Quadratic Equation", "We solve using the quadratic formula:", "[
\nn = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\n]", "Substitute values:", "[
\nn = \dfrac{-2 \pm \sqrt{(2)^2 - 4(1)(-210)}}{2(1)} = \dfrac{-2 \pm \sqrt{4 + 840}}{2} = \dfrac{-2 \pm \sqrt{844}}{2}
\n]", "Simplify ( \sqrt{844} ):", "[
\n\sqrt{844} = \sqrt{4 \cdot 211} = 2\sqrt{211}
\n]", "So,", "[
\nn = \dfrac{-2 \pm 2\sqrt{211}}{2} = -1 \pm \sqrt{211}
\n]", "Since ( n ) must be a positive real number (typically representing a measurable quantity like length or count), we take the positive root:", "[
\nn = -1 + \sqrt{211}
\n]", "---", "### Approximate Value", "Estimate ( \sqrt{211} ): since ( 14^2 = 196 ) and ( 15^2 = 225 ), ( \sqrt{211} \approx 14.53 ). Thus:", "[
\nn \approx -1 + 14.53 = 13.53
\n]", "However, since the original equation implies a discrete solution (e.g., number of objects or steps), check if an integer solution exists.", "Try factoring ( n^2 + 2n - 210 = 0 ):", "Find two numbers multiplying to ( -210 ) and adding to ( 2 ).", "Factors: ( 15 ) and ( -14 ), since ( 15 \ imes (-14) = -210 ) and ( 15 + (-14) = 1 ) — too small.", "Try ( 16 \ imes (-13.125) ) — non-integer.", "Try ( 14 \ imes (-15) = -210 ), sum ( -1 ) — no.", "Try ( 21 \ imes (-10) = -210 ), sum ( 11 )", "Eventually, test integer close to 13:", "Try ( n = 14 ):", "[
\n14^2 + 2(14) - 210 = 196 + 28 - 210 = 14 <br/>\neq 0
\n]", "Try ( n = 13 ):", "[
\n13^2 + 26 - 210 = 169 + 26 - 210 = -15
\n]", "Try ( n = 15 ):", "[
\n225 + 30 - 210 = 45
\n]", "Since no integer solution satisfies exactly, the exact solution remains irrational:", "[
\n\boxed{n = -1 + \sqrt{211}}
\n]", "---", "### Real-World Application", "Such quadratic equations model scenarios like area calculations, projectile motion, or financial growth over discrete steps. Although ( n = -1 + \sqrt{211} ) is not an integer, it represents a precise algebraic answer useful for modeling and computation in scientific or engineering contexts.", "---", "### Summary", "Solving ( \dfrac{n}{2}(6 + 2n - 2) = 210 ) reduces to solving ( n^2 + 2n - 210 = 0 ), with exact solution:", "[
\nn = -1 + \sqrt{211} \approx 13.53
\n]", "This equation exemplifies how rational manipulation and quadratic formulas unlock deeper mathematical understanding, applicable in physics, economics, and computer science.", "---", "Keywords:
\nquadratic equation, solve ( \dfrac{n}{2}(6 + 2n - 2) = 210 ), algebraic solution, quadratic formula, ( n = -1 + \sqrt{211} ), exponential growth, real-world equations, math problem solving.", "---", "Tips for Learners:
\n- Always simplify expressions before forming equations.
\n- Check solutions by substitution.
\n- Understand hole concepts and rational solutions.
\n- Use calculators wisely to verify roots and estimates.", "---", "### Further Reading
\n- Quadratic Equations and Applications
\n- Solving Radical Equations
\n- Real-World Problems Using Algebra", "---", "Stay curious, keep solving — every equation tells a story beneath the numbers."]