Set \( h(t) = 0 \):
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- Dimensions are 10 meters by 24 meters.
- #### 10 meters by 24 meters
- A ball is thrown upwards with an initial velocity of 20 m/s from a height of 50 meters. Using the equation \( h(t) = -5t^2 + 20t + 50 \), where \( h \) is the height in meters and \( t \) is the time in seconds, find the time when the ball hits the ground.
- \( -5t^2 + 20t + 50 = 0 \)
- Divide the entire equation by -5:
- \( t^2 - 4t - 10 = 0 \)
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