t = 2: -10/16 = -0.625

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• But this is not among choices. Let’s compute exactly:
• Try \( t = 1 \):
• C'(1) = -10/(3^2) = -10/9 \approx -1.11
• No integer gives exactly – but let’s test option B: gives -10/9 ≈ -1.11 ≠ -1
• Wait — perhaps solve:
• \frac{10}{(t+2)^2} = 1 \Rightarrow t+2 = \sqrt{10} \Rightarrow t = \sqrt{10} - 2 \approx 3.16 - 2 = 1.16

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